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Question about invokeChaincode api #fabric-chaincode
BigBang019
Thank you guys so much, it's really helpful!
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Hi! The chaincode has a unique identifier in the network when it is running. If a chaincode calls itself (another function) using invokeChaincode method, an error will occur. You have to call the function directly without using invokeChaincode method. If a chaincode invokes another chaincode in the same channel, both calls will have their write sets appended to the transaction. If a chaincode invokes another chaincode in another channel, it will be considered a query and no changes will be applied to the second chaincode state. Best regards. David Em sex., 17 de dez. de 2021 às 08:24, BigBang019 <zhuxy0000@...> escreveu:
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David Reis
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BigBang019
Thanks for your attention: https://github.com/hyperledger/fabric-chaincode-java/issues/218
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Matthew White
Hello;
Can I suggest that you raise an issue on the github hyperledger/fabric-chaincode-java repo?
Though to check that you can call `helloworld()` directly from `invokeChaincode` without having to call invokeChaincode? Pass on the ctx variable, and both methods are then part of the same transaction.
Typically only use invokerChaincode, when you going to a completely different chaincode.
Regards, Matthew.
Matthew B White IBM Blockchain Solutions Architect
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BigBang019
Environment: fabric release-2.2
My chaincode named vulnerable is as follows: When I invoke helloworld directly, it gives me responce "helloworld", everything works fine. But when I invoke invokeChaincode method, it gives me and chaincode docker container logging is as follows: It seems like (1) the statement System.out.printf("\n%s\n", chaincodeName) works fine. (2) org.hyperledger.fabric.shim.impl.InvocationStubImpl.invokeChaincode also finds the registered method helloworld, but it encountered another exception half way the invocation. Does anyone met this problem before? Thanks in advance.
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